In an electric shaver the blade moves back and forth

Answer:

(A)  0.001 m  

(B) 0.75 m/s  

(C) 5.7 x 10^{2} m/s^{2}      

Explanation:

distance (d) = 2 mm

frequency (f) = 120 Hz

(A) amplitude (A) = half the distance moved by the blade

      amplitude = 2 / 2 = 1 mm = 0.001 m

(B) maximum blade speed (v) = ωA = 2πfA

     v = 2 x 3.14 x 120 x 0.001 = 0.75 m/s  

(c) maximum blade acceleration (a) = w^{2}A

     a = (2 x 3.14 x 120)^{2}x0.001 = 5.7 x 10^{2} m/s^{2}

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